x^2+x/x^2-6x+8/x^2+3x+2/2x^2-7x+6 can some help me please...

Factor each term; you will find that some terms may cancel out. For example, x^2 + x = x(x + 1) and x^2 + 3x + 2 = (x + 1)(x + 2). Also use the properties of fractions with multiplicative inverses: ( (x^2 + x) / (x^2 - 6x + 8) ) / ( (x^2 + 3x + 2) / (2x^2 - 7x + 6) ) = ( (x^2+x) / (x^2 - 6x + 8) ) * ( (2x^2 - 7x + 6) / (x^2 + 3x + 2)

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