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Q)1 : Alpha particles travel through a magnetic field of 0.360T and are deflected in an arc of 0.0820m. Assuming the alpha particle are perpendicular to the field, what is the energy of an individual alpha particle?

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Marium

  1. calculate the velocity:

    Bqv=Force

    and force= massalpha*v^2/r
    bqv=massv^2/r
    solve for v.

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    bobpursley

  2. do i use the value of q/m ratio??

    and thank u =)

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    Marium

  4. Magnetic field B = 0.36 T
    Deflected radius of an arc r = 0.082 m
    Charge of alpha particle q = 2e = 3.20435 × 10^-19 C
    Mass of alpha particle m = 6.64 × 10^−27 kg
    Magnetic Force = Bqv
    Centripetal Force = mv²/r
    Bqv = mv²/r
    v = Bqr/m
    v = (0.36)( 3.20435 × 10^-19)( 0.082) / (6.64 × 10^−27)
    v = 1.42458 × 10^6 m/s

    Energy of alpha particle E = (1/2)mv²
    E = (1/2)( 6.64 × 10−27)( 1.42458 × 106)²
    E = 4.7296 × 10^−15 J
    Energy of alpha particle is 4.7296 × 10^−15 J.

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    jeevakiran

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