the molar heat of vaporization for water is 40.79 kJ/mol. How would you express this heat of vaporization in joules per gram.

40.79kj/mol =j/g

Well, if you're a water molecule, I bet you'd be pretty hot with all that vaporization going on! Now, let's put the lab coat on and do some math, shall we?

First off, we need to convert the molar heat of vaporization from kilojoules per mole (kJ/mol) to joules per mole (J/mol). Remember, there are 1000 joules in a kilojoule. So, 40.79 kJ/mol is equal to 40,790 J/mol.

Next, we'll convert the molar heat of vaporization to joules per gram. To do this, we need to know the molar mass of water, which is approximately 18.01528 grams/mol.

Lastly, we divide the molar heat of vaporization by the molar mass of water to find the heat of vaporization in joules per gram. Let's do some more math:

40,790 J/mol / 18.01528 grams/mol ≈ 2264 J/gram

Voilà! The heat of vaporization for water is roughly 2264 joules per gram. Keep cool, my friend!

To express the molar heat of vaporization in joules per gram, you need to convert it from kilojoules per mole to joules per gram. Here's how you can do it step-by-step:

Step 1: Convert kJ/mol to J/mol:
To convert kilojoules (kJ) to joules (J), you need to multiply by 1000 since there are 1000 joules in one kilojoule. Therefore, multiply the given molar heat of vaporization by 1000:
40.79 kJ/mol * 1000 J/kJ = 40790 J/mol

Step 2: Convert J/mol to J/g:
To convert from moles (mol) to grams (g), you need to know the molar mass of water. The molar mass of water (H2O) is approximately 18.015 g/mol. Divide the molar heat of vaporization by the molar mass to convert it to joules per gram:
40790 J/mol / 18.015 g/mol ≈ 2265 J/g (rounded to three significant figures)

Therefore, the molar heat of vaporization for water can be expressed as approximately 2265 J/g.

To express the molar heat of vaporization in joules per gram, you need to convert the units appropriately.

Here's how you can do it:

Step 1: Convert the given molar heat of vaporization from kilojoules per mole (kJ/mol) to joules per mole (J/mol). Since 1 kilojoule (kJ) is equal to 1000 joules (J), multiply the given value by 1000 to convert it to joules.
40.79 kJ/mol * 1000 J/kJ = 40,790 J/mol

Step 2: Convert the molar amount to a mass amount. To do this, you need to know the molar mass of water, which is approximately 18.015 grams per mole (g/mol).

Step 3: Divide the molar heat of vaporization (in joules) by the molar mass (in grams) to obtain the heat of vaporization in joules per gram.

40,790 J/mol / 18.015 g/mol ≈ 2260 J/g

Therefore, the molar heat of vaporization for water, 40.79 kJ/mol, is approximately equal to 2260 J/g when expressed in joules per gram.

40,790 J/mole divide by 18 g/mole

= 2266 J/g
= 542 calories/g