How many joules of heat are lost by 3399kg granite as it cools from 41.7 degrees Celcius to -13.3 degrees Celcius? answer must be in joules not kJ

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  1. q = mass granite x specific heat granit x delta T.

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  2. ok so,

    q=3399kg x 0.803 x 55
    q = 150.116

    Is that correct?

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  3. so then my answer would be 150.116kJ which equals 150116835J. Is that correct???

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