Alg

How would you evaluate this n^(log(n lowered)3)?

I don't know how to make the n lower than the log.

What would the answer be?

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  1. one of the fundamental properties of logs is that

    aloga k = k

    (hope this came out ok)

    e.g. (one we can actually evaluate)

    2log2 8 = 8

    so for your problem the answer would be 3

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    posted by Reiny

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