Algebra II

How would you evaluate this n^(log(n lowered)3)?

I don't know how to make the n lower than the log.

What would the answer be?

  1. 👍
  2. 👎
  3. 👁

Respond to this Question

First Name

Your Response

Similar Questions

  1. Trigonometry

    This is a logs question If u=x/y^2, which expression is equivalent to log u? 1) log x + 2 log y 2) 2(log x- log y) 3) 2(log x + log y) 4) log x- 2 log y

  2. Chemistry

    When a wooden log burns it is essentially undergoing a combustion reaction. Explain why the ashes that form when a log burns have a lower mass than the log had before it started burning.

  3. algebra

    Use log 3=0.477 and log 5=0.699 to evaluate the logarithm. log45

  4. math(Please help)

    1) use the properties of logarithms to simplify the logarithmic expression. log base 10 (9/300) log - log 300 log 9 = 2 log 3 log 300 = log 3 + log 100 = log 3+2 I just do not know how to put these together now!

  1. Math

    If ln a=2, ln b=3, and ln c=5, evaluate the following: (a) ln(a^−2/b^4c^−3)= -.9524 (b) ln(√b^−4*c^1*a^−1)= -1.739 (c) ln(a^2b^4)/ln(bc)^−2= 42.39 (d) (ln(c^−1))*(ln(a/b^3))^−4= -.03507 I am getting these answers

  2. pre calculous

    use the properties of logarithms to write the expression as a sum or difference of logarithms or multiples of logarithms. show your work ln x^2/y^3 Assuming x,y AND z are positive use properties of logariths to write the

  3. Math

    Evaluate Log4^5-log5^4/log 4^1/5+log 5^1/4

  4. math

    evaluate without using a calculator [log(5)4 x log(2)10 ]/ [log(25)√10]

  1. Re: Algebra II

    How to solve Log (9x+5) - Log ((x^2)-1) = 1/2 16 16 (The 16 is from the logarithmic function : b) (y=log x) b Could anyone post the answer to this? 16 is supposed to be next to Log(16) but lower. This is for both the Logs in the

  2. Pre Calculus

    Evaluate log b {square root of 10b}, given that log b 2 = 0.3562 and log b 5 = 0.8271 (sorry I had no clue how to type this in math format!)

  3. math

    Given that log 4 = 0.6021 and log 6 = 0. 7782, evaluate log 0.096

  4. algebra/logs

    I don't understand this problem: (1/2)n = 0.015625 n log 0.5 = log 0.015625 n = log 0.5 / log 0.015625 n = 6 When I plug log .5 into the calculator it gives .3010 and when I plug .15625 to the calculator it is -1.806 and that

You can view more similar questions or ask a new question.