How many individual hydroxide ions (OH)- are found in 13.4mL of 0.586M Ba(OH)2?

I'm not quite sure how to do this. Thank you!

How many moles Ba(OH)2 do you have?

moles = M x L.
There will be twice the molar concn of OH^- because there are two OH ions/1 molecule Ba(OH)2.
There are 6.022 x 10^23 OH^- in a mole of them. How many in the number of moles you have? Go from there.

9.45e21

idk lmao

Well, let's dive into the world of hydroxide ions! Ba(OH)2 consists of one barium ion (Ba2+) and two hydroxide ions (OH-). That means for every mole of Ba(OH)2, we have two moles of OH-.

First, we need to find the number of moles of Ba(OH)2 in 13.4 mL. To do that, we can use the formula:

moles = volume (in liters) x concentration (in moles per liter)

Converting 13.4 mL to liters:

13.4 mL = 0.0134 L

Now, let's calculate the number of moles:

moles = 0.0134 L x 0.586 M = 0.007834 moles

Since there are 2 moles of OH- for every mole of Ba(OH)2, we can double the number of moles we calculated to find the number of moles of OH-.

2 x 0.007834 = 0.015668 moles of OH-

But you asked for the number of individual hydroxide ions. In 1 mole of any substance, there is Avogadro's number of particles, which is approximately 6.022 x 10^23. So, in 0.015668 moles of OH-, there would be:

0.015668 moles x 6.022 x 10^23 molecules/mole = 9.437 x 10^21 individual hydroxide ions

So, in 13.4 mL of 0.586M Ba(OH)2, there are approximately 9.437 x 10^21 individual hydroxide ions. That's quite a crowd of OH- ions!

To determine the number of individual hydroxide ions (OH)- in a given compound, you need to consider the stoichiometry of the compound. In the case of Ba(OH)2, there are two hydroxide ions for every one Ba2+ ion.

To calculate the number of hydroxide ions, you can follow these steps:

Step 1: Convert the given volume from milliliters (mL) to liters (L).
13.4 mL = (13.4 mL) / (1000 mL/L) = 0.0134 L

Step 2: Calculate the number of moles of Ba(OH)2 using the formula:
moles = concentration (M) × volume (L)
moles = 0.586 M × 0.0134 L = 0.0078224 moles

Step 3: Use the stoichiometry of Ba(OH)2 to determine the number of moles of hydroxide ions.
Since there are two hydroxide ions for every one Ba(OH)2 molecule, the number of moles of OH- ions is twice the number of moles of Ba(OH)2.
moles of OH- = 2 × 0.0078224 moles = 0.0156448 moles

Step 4: Convert the number of moles of OH- ions to the number of individual hydroxide ions.
Avogadro's number (6.022 × 10^23) represents the number of particles (atoms, molecules, or ions) in one mole of a substance. Therefore, we can calculate the number of individual hydroxide ions by multiplying the number of moles of OH- ions by Avogadro's number.
number of individual OH- ions = 0.0156448 moles × (6.022 × 10^23) = 9.4 × 10^21 OH- ions

Therefore, there are approximately 9.4 × 10^21 individual hydroxide ions (OH)- in 13.4 mL of 0.586 M Ba(OH)2.