One side of a triangle is 15 inches, and the area of the triangle is 90 square inches. What is the area of a similar triangle in which the corresponding side is 9 inches?
Why not use the concept I showed you in
http://www.jiskha.com/display.cgi?id=1274147511
for a similar problem.
let me know what you got for this one.
i don't understand this
To find the area of the similar triangle, we can use the concept of similarity ratios. The ratio of the corresponding sides of two similar triangles is equal to the ratio of their areas.
In this case, we have a larger triangle with a side length of 15 inches and an area of 90 square inches, and a smaller triangle with a corresponding side length of 9 inches. We need to find the area of the smaller triangle.
Let's set up a proportion using the sides of the two triangles:
15/9 = 90/x
Cross-multiplying, we get:
15x = 9 * 90
Simplifying, we have:
15x = 810
Now, divide both sides of the equation by 15:
x = 54
Therefore, the area of the similar triangle with a corresponding side length of 9 inches is 54 square inches.
area2/90 = 15^2/9^2
area2/90 = 225/81
area2 = 90(225)/81 = 250