64y^3-125
8x^3+125
Please help me I do not understand.
Must done today.
Are both equations supposed to be set to zero???
they are factor complete or state that the polynomial is prime.
64y^3-125
8x^3+125
so help me please.
We can factor both the difference and the sum of 2 cubes
A^3 - B^3 = (A-B)(A^2 + AB + B^2)
A^3 + B^3 = (A+B)(A^2 - AB + B^2)
64y^3 - 125
= (4y-5)(16y^2 + 20y + 25)
you try the second one
8x^3+125=(4-5)(2x^2+20+25)
the problem is about factor complete, or state that the polynomial is prime.
could you check and see if I got it right.
To simplify the expressions and help you understand, let's break them down:
Expression 1: 64y^3 - 125
This expression is a difference of cubes. To simplify it, we can use the formula:
a^3 - b^3 = (a - b)(a^2 + ab + b^2)
In expression 1, a = 4y and b = 5:
64y^3 - 125 = (4y - 5)(16y^2 + 20y + 25)
So, the simplified form of expression 1 is:
(4y - 5)(16y^2 + 20y + 25)
Expression 2: 8x^3 + 125
This expression can also be simplified as a sum of cubes. The formula for sum of cubes is:
a^3 + b^3 = (a + b)(a^2 - ab + b^2)
In expression 2, a = 2x and b = 5:
8x^3 + 125 = (2x + 5)(4x^2 - 10x + 25)
So, the simplified form of expression 2 is:
(2x + 5)(4x^2 - 10x + 25)
Remember to always check if the expression can be factored further, and if necessary, simplify or factor using other applicable techniques.