# algebra

64y^3-125

8x^3+125

Please help me I do not understand.
Must done today.

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1. Are both equations supposed to be set to zero???

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2. they are factor complete or state that the polynomial is prime.
64y^3-125

8x^3+125

so help me please.

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3. We can factor both the difference and the sum of 2 cubes
A^3 - B^3 = (A-B)(A^2 + AB + B^2)
A^3 + B^3 = (A+B)(A^2 - AB + B^2)

64y^3 - 125
= (4y-5)(16y^2 + 20y + 25)

you try the second one

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4. 8x^3+125=(4-5)(2x^2+20+25)
the problem is about factor complete, or state that the polynomial is prime.

could you check and see if I got it right.

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