physics

An object with a height of 42 cm is placed 1.6 m in front of a concave mirror with a focal length of 0.45 m. Find the location and magnification of the image produced by the mirror, using the mirror and magnification equations.

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asked by Cole
  1. First, you need to learn the equations. It's not that hard.

    1/Do + 1/Di = 1/f

    Do is the object distance from the mirror and Di is the distance to the image from the mirror. f is the focal length.

    Use that equation to solve for Di.


    1/1.6 + 1/Di = 1/0.45
    1/Di = 1.597
    Di = 0.6261 m

    The magnification is M = Di/Do.

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    posted by drwls

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