Math

Use the discriminate to determine how many real number solutions the equation has.

s^2 - 5s + 6 = 0

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  1. the discriminant= b2-4ac
    a=1 b=-5 c=6
    25-4(1)(6)=1
    Since 1 > 0, the polynomial has two real roots, if the discriminant = 0, the polynomial has one real root, and if it's < 0, the polynomial has no real roots

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  2. I still don't understand. Could you explain. I don't know what any of this means.

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  3. When you have an equation, s^2-5s+6=0, you can find the discriminant by b^2-4ac. The co-efficient (what comes before) the squared term is a, in this case 1. The co-efficient before the s is b (-5), and the last term is c (6). 25-4(1)(6)=1. When it is more than 0, the polynomial has two real roots (or answers). If the discriminant is equal to 0, the polynomial has one real root, and if it's less than 0, the polynomial has no real roots. For this problem, since the discriminant equals 1, it has two real roots. I hope this helps. It's hard to explain through the internet. If you still don't understand, try asking your teacher.

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