what is the molarity of 5.00 g of Na2CO3 dissolved n 400.0 mL solution?
Your School Subject is probably chemistry.
i think the formula to find this out is either g/l or l/g --- use the internet, google molarity formula
# of moles= 0.05
volume= 0.4L
Molarity= 0.125M
To find the molarity (M) of a solution, you need to know the number of moles of solute (Na2CO3) and the volume of the solution in liters.
Step 1: Convert the given mass of Na2CO3 into moles.
To do this, you need the molar mass of Na2CO3. The molar mass of Na is 22.99 g/mol, of C is 12.01 g/mol, and of O is 16.00 g/mol. Since Na2CO3 contains 2 Na atoms, 1 C atom, and 3 O atoms, the molar mass of Na2CO3 is (2 * 22.99 g/mol) + 12.01 g/mol + (3 * 16.00 g/mol).
Molar mass of Na2CO3 = (2 * 22.99 g/mol) + 12.01 g/mol + (3 * 16.00 g/mol)
= 105.99 g/mol
Now, you can calculate the number of moles of Na2CO3 using the given mass and molar mass.
Number of moles = Mass of Na2CO3 / Molar mass
= 5.00 g / 105.99 g/mol
Step 2: Convert the given volume of the solution from milliliters to liters.
There are 1000 milliliters (mL) in 1 liter, so you need to divide the given volume by 1000 to convert it to liters.
Volume of solution in liters = 400.0 mL / 1000
Step 3: Calculate the molarity (M) using the formula:
Molarity (M) = Number of moles / Volume of solution (in liters)
Molarity (M) = Number of moles / Volume of solution in liters
= (5.00 g / 105.99 g/mol) / (400.0 mL / 1000)
Now, you can substitute the values into the formula and calculate the molarity.