intermidiate algebra

converting to LCD

3/4b^-9, 2/2b+3, -5/2b^-3b

that sign over the "b"represent 2
I have to work this problem so help me.

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  1. so your denominators are
    4b^2 - 9 or (2b+3)(2b-3)
    2b+3 and
    2b^2 - 3b or b(2b-3)

    our LCD must have each of those appearing, then the
    LCD = .....

    let me know what your answer is

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