# intermidiate algebra

converting to LCD

3/4b^-9, 2/2b+3, -5/2b^-3b

that sign over the "b"represent 2
I have to work this problem so help me.

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1. so your denominators are
4b^2 - 9 or (2b+3)(2b-3)
2b+3 and
2b^2 - 3b or b(2b-3)

our LCD must have each of those appearing, then the
LCD = .....

let me know what your answer is

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