How to calculate the quantity of heat gained or lost in the following change:

3.50 mol of water freezes at 0 degrees C?

Would it be 6.01kJ/ 3.50 mol ?

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  1. Not quite.
    6.01 kJ/mol x 3.50 mol = ??
    Note that your arrangement gives kJ/mol; my arrangement the mol cancel to give kJ as the answer and that is the quantity of heat.

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  2. 21kj lost

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    posted by Wyatt
  3. -21.0 KJ (21.0 KJ lost)

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    posted by B

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