8 csc theta - 2=10 + 2 csc theta
I can't do it. :S
No worries! I can help you with that.
To solve the equation 8cscθ - 2 = 10 + 2cscθ, we want to isolate the variable θ.
First, let's combine the terms that contain cscθ. We have 8cscθ on the left side and 2cscθ on the right side. To get these terms on the same side, we can subtract 2cscθ from both sides of the equation:
8cscθ - 2cscθ - 2 = 10
Simplifying, we have 6cscθ - 2 = 10.
Next, let's isolate the term with cscθ. We can do this by adding 2 to both sides of the equation:
6cscθ - 2 + 2 = 10 + 2
Simplifying, we have:
6cscθ = 12
Finally, to solve for cscθ, we can divide both sides of the equation by 6:
(6cscθ)/6 = 12/6
Simplifying, we have:
cscθ = 2
Now that we have cscθ = 2, you can find the corresponding values of θ by taking the inverse cosecant (or arcsine) of 2. This will give you the angle(s) that have a cosecant value of 2.
I hope this helps! Let me know if you have any further questions.