5-x/x^2-8x+15.
can you show steps on how to solve this? thank you.
what's the question asking?
the zeroes of the function?
the domain?
in this case, if you want to find the domain
you have to factor the bottom
(5-x)/[(x-3)(x-5)]
and because you know the denominator cannot be zero because that will make the problem undefined, the domain would be
(negative infinite, 3) U (3,5) U (5, infinite)
Does the question say, "simplify" ??
then ...
(5-x)/(x^2-8x+15)
= (5-x)/[(x-3)(x-5)]
= - 1/(x-3) , x ≠ 5, 3
Certainly! To simplify the expression 5 - x / (x^2 - 8x + 15), we can follow these steps:
Step 1: Factor the denominator (x^2 - 8x + 15):
The quadratic expression can be factored as (x - 3)(x - 5). So, the denominator becomes (x - 3)(x - 5).
Step 2: Rewrite the expression:
Now, we have 5 - x / (x - 3)(x - 5).
Step 3: Simplify the numerator:
The numerator remains the same: 5 - x.
Step 4: Write the expression with the simplified numerator:
Now, the expression is (5 - x) / (x - 3)(x - 5).
This is the simplified form of the given expression.