# Algebra

5-x/x^2-8x+15.
can you show steps on how to solve this? thank you.

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1. what's the question asking?
the zeroes of the function?
the domain?

in this case, if you want to find the domain
you have to factor the bottom
(5-x)/[(x-3)(x-5)]
and because you know the denominator cannot be zero because that will make the problem undefined, the domain would be
(negative infinite, 3) U (3,5) U (5, infinite)

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posted by Harry
2. Does the question say, "simplify" ??

then ...

(5-x)/(x^2-8x+15)
= (5-x)/[(x-3)(x-5)]
= - 1/(x-3) , x ≠ 5, 3

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posted by Reiny

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