Algebra

5-x/x^2-8x+15.
can you show steps on how to solve this? thank you.

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  1. what's the question asking?
    the zeroes of the function?
    the domain?

    in this case, if you want to find the domain
    you have to factor the bottom
    (5-x)/[(x-3)(x-5)]
    and because you know the denominator cannot be zero because that will make the problem undefined, the domain would be
    (negative infinite, 3) U (3,5) U (5, infinite)

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    posted by Harry
  2. Does the question say, "simplify" ??

    then ...

    (5-x)/(x^2-8x+15)
    = (5-x)/[(x-3)(x-5)]
    = - 1/(x-3) , x ≠ 5, 3

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    posted by Reiny

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