Algebra

5-x/x^2-8x+15.
can you show steps on how to solve this? thank you.

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asked by Aasthaaaaa

  1. what's the question asking?
    the zeroes of the function?
    the domain?

    in this case, if you want to find the domain
    you have to factor the bottom
    (5-x)/[(x-3)(x-5)]
    and because you know the denominator cannot be zero because that will make the problem undefined, the domain would be
    (negative infinite, 3) U (3,5) U (5, infinite)

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    posted by Harry

  2. Does the question say, "simplify" ??

    then ...

    (5-x)/(x^2-8x+15)
    = (5-x)/[(x-3)(x-5)]
    = - 1/(x-3) , x ≠ 5, 3

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    posted by Reiny

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