# Vectors

Cross product of vector:

If axb(cross product)=(2,0,1) and bxc= -4,0,-4

solve magnitude of axb times magnitude of b x c

|a x b| x|bxc|

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1. |(2,0,1)| = √(4+0+1) = √5
|(-4,0,-4)| = √(16+0+16) = √32

so their product is √5√32 = √60 = 2√15

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posted by Reiny

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