If the pattern of the first letters of MATHMATHMATH……continues to the right, the 1989th letter would be?
..M A T H
..1 2 3 4
.25 .5 .75 1
1989/4 = 497.25 making the 1989th digit an M.
To find the 1989th letter in the pattern, we need to determine the repeating pattern in the sequence. The given sequence is "MATH" repeated.
Since "MATH" has 4 letters, we can divide 1989 by 4 to find how many complete repetitions of "MATH" are in the sequence.
1989 ÷ 4 = 497 remainder 1
So, we can conclude that there are 497 complete repetitions of "MATH" in the given sequence.
Now, to find the 1989th letter, we need to identify the position of the remainder, which is 1. This means that after the complete repetitions of "MATH," we need to find the first letter of the pattern, which is "M."
Therefore, the 1989th letter in the sequence would be "M."
To find the 1989th letter in the pattern of the first letters "MATHMATHMATH...", we need to understand the pattern and then determine which letter corresponds to the given position.
The given pattern suggests that the letters "MATH" are repeating. The pattern length is 4 because there are four distinct letters in the sequence. Therefore, every fourth letter will be the same.
To find the position of the 1989th letter in the pattern, we can divide the position by the length of the pattern and determine the remainder. If the remainder is zero, then the letter would be "H" because it is the fourth letter in the pattern. Otherwise, we can use the remainder to identify the corresponding letter.
Let's calculate the position of the 1989th letter in the pattern:
1989 divided by 4 equals 497 with a remainder of 1.
Since the remainder is 1, we know that the letter at the 1989th position would be the second letter in the pattern, which is "A".
Therefore, the 1989th letter in the pattern "MATHMATHMATH..." would be "A".