How many moles of NaOH are contained in 100.0 mL of 3.00 M NaOH?
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.300
moles = M x L.
To find the number of moles of NaOH, you can use the formula:
moles = concentration (M) x volume (L)
First, convert the volume from milliliters (mL) to liters (L):
100.0 mL = 100.0 mL / 1000 mL/L = 0.100 L
Now, plug in the values into the formula:
moles = 3.00 M x 0.100 L
moles = 0.300 mol
Therefore, there are 0.300 moles of NaOH in 100.0 mL of 3.00 M NaOH.
To find the number of moles of NaOH, you will need to use the formula:
moles = concentration × volume
Given that the concentration is 3.00 M and the volume is 100.0 mL, you can now substitute these values into the formula:
moles = 3.00 M × 100.0 mL
However, before calculating, it is recommended to convert the volume from milliliters (mL) to liters (L). Since 1 L = 1000 mL, the volume can be converted as follows:
volume = 100.0 mL ÷ 1000 mL/L
volume = 0.100 L
Now, substitute the values into the formula:
moles = 3.00 M × 0.100 L
Simplifying the calculation:
moles = 0.300 mol
Therefore, there are 0.300 moles of NaOH in 100.0 mL of 3.00 M NaOH.