ln(x-5)+ln(x+4)=ln36

are we solving for x ?? if so, then ln[(x-5)(x+4)] = ln36 "anti-ln" it (x-5)(x+4) = 36 x^2 - x -56 = 0 (x-8)(x+7) = 0 x = 8 or x = -7 but x=-7 would make the original undefined, so x = 8

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