algebra

ln(x-5)+ln(x+4)=ln36

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  1. are we solving for x ??

    if so, then
    ln[(x-5)(x+4)] = ln36
    "anti-ln" it

    (x-5)(x+4) = 36
    x^2 - x -56 = 0
    (x-8)(x+7) = 0
    x = 8 or x = -7

    but x=-7 would make the original undefined, so
    x = 8

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