what is the ration of water drops to EDTA (ethylenediamene tetraacetic acid) if 3 drops of EDTA was needed to change the color of 20 drops of water with known hardness??
a. 0.15
b. 1.0
c. 4.0
d. 6.7
am I missing something huge here??
water:Etda::20:3
D is the answer
what about this??
what is the ratio of water drops to EDTA if 2 DROPS of EDTA was needed to change the color of 20 drops of water with UNKNOWN HARDNESS?
a. 10
b. 5
c. 0.1
d. 1.0
To find the ratio of water drops to EDTA, we need to compare the number of drops of EDTA to the number of drops of water.
In this case, 3 drops of EDTA were needed to change the color of 20 drops of water.
To find the ratio, we divide the number of drops of water by the number of drops of EDTA:
Ratio = Number of drops of water / Number of drops of EDTA
In this case, the ratio would be:
Ratio = 20 drops of water / 3 drops of EDTA
To simplify the ratio, we divide both the numerator and denominator by the greatest common divisor (GCD) of 20 and 3, which is 1.
Ratio = (20 / 1) / (3 / 1) = 20 / 3 ≈ 6.7
Therefore, the correct answer is option (d) 6.7.