Calculate the force in Newtons that exists between a positive charge of 2C and a negative charge of 5.2 X 10^19 electrons separated by a distance of 25 cm.
f=kqq/r^2
I will be happy to critique your work.
I'm having trouble finding Q2.
-5.2 x 10^19 x 6.2 x 10 ^18?
The "Q2" charge, of the 5.2*10^19 electrons, is
-5.2*10^19*1.6*10^-19 C/electron
= -8.32 Coulombs
Your number of 6.2*10^18 is the number of electrons per Coulomb. If you had divided by that number instead of multiplying, you would have gotten the right answer.
To calculate the force between two charges, you can use Coulomb's Law. Coulomb's Law states that the force, F, between two charges, q1 and q2, separated by a distance, r, is given by the equation:
F = k * |q1 * q2| / r^2
Where:
F is the magnitude of the force,
k is Coulomb's constant (9 x 10^9 N m^2/C^2),
|q1| and |q2| are the magnitudes of the charges, and
r is the distance between the charges.
In this case, we have a positive charge of magnitude 2C and a negative charge of 5.2 x 10^19 electrons. We need to convert the charge of the electrons to Coulombs.
The charge of an electron is -1.6 x 10^-19 C (Coulombs). Therefore, the charge of 5.2 x 10^19 electrons is:
q2 = (-1.6 x 10^-19 C/electron) * (5.2 x 10^19 electrons)
= -8.32 C
Now we can substitute the values into the equation and solve for the force:
F = (9 x 10^9 N m^2/C^2) * |2C * (-8.32 C)| / (0.25 m)^2
= (9 x 10^9 N m^2/C^2) * 16.64 C^2 / 0.0625 m^2
= (9 x 10^9 N m^2/C^2) * 266.24 C^2 / 0.0625 m^2
= (9 x 10^9 N m^2/C^2) * 4259.84 C^2 / m^2
≈ 3.832 x 10^14 N
Therefore, the force between the charges is approximately 3.832 x 10^14 Newtons.