# science/chemistry

Qc for the following chemical reaction
3CIO2-(aq)<-->2CIO3-(aq)+Cl-(aq)
Choices
A:3[CIO2-]/2[CIO3-][Cl}
B:2[CIO3-][Cl]/3[CIO2-]
C:[CIO2-]^3/[CIO3-]^2[Cl-]
D:[CIO3-]^2[Cl-]/[CIO2-]^3

I like B: what would you go for??
thanks all

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3. 👁 103
1. Qc = same as Kc for this.
Kc = (product)^x(product)^y/(reactant)^z
where x, y, and z are the coefficients in the balanced equation.
In words it goes like this. The product of the products of a reaction divided by the product of the reactants, each raised to a power indicated by the coefficients in the balanced chemical equation, is a constant. This is called the equilibrium constant. [In this case it is the "reaction quotient".]
I don't like B.

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2. Dr Bob
I don't like B or C or D
that only leaves A
Is this what you would go for ????
Thanks andy

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posted by Stuck
3. Do what the words say do. Do what my equation says to do.

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4. Aha its actually A???
Correct???

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posted by ANDY
5. You must be guessing. The answer is D.
If you followed my equation OR the words I wrote, you would KNOW it is D.
The product of the products of the reaction, divided by the product of the reactants (that eliminates A and C because the reactants are the numerator), each raised to a power indicated......etc (that eliminates B because those are coefficients and not exponents. It MUST be between C and D because those are the ONLY two that use exponents and it can't be C because the reactants are in the numerator and the products are in the denominator.

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6. Oh I see now that you explained it that way!!!!
OOPS....sorry yes I took a stab in the dark.....One day I may get this stuff....its going to be a long trip....How do YOU remember all this???
My heads about to explode and I am too young to die!!!!!!!!

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posted by Andy
7. The words I quoted above are the EXACT words my freshman chemistry professor used to explain Keq 62 years ago. I can remember all of that stuff I learned years ago---it's the recent stuff I have trouble with. I work a problem today with new information and forget tomorrow how I did it and must do it again from scratch.

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