when a 0.4-g almond sample is burned the heat gained by the water is 7525.4 J and the temperature of the water increased from 24 C to 58 C what was the mass of the water in grams?
a. 50
b. 100
c. 45
d. 52.9
q = mass water x specific heat water x (Tfinal-Tinitial).
the answer I got was 52.9... right??
To find the mass of the water, we can use the formula:
q = mcΔT
where q is the heat gained or lost by the water, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature of the water.
Given:
q = 7525.4 J
ΔT = (58°C - 24°C) = 34°C
The specific heat capacity of water is approximately 4.18 J/g°C.
Plugging the values into the formula:
7525.4 J = m * 4.18 J/g°C * 34°C
Simplifying:
7525.4 J = 141.72 m
Dividing both sides by 141.72:
m = 7525.4 J / 141.72 J/g°C
m ≈ 53.09 g
The mass of the water in grams is approximately 53.09 g.
Therefore, the closest option is d. 52.9 g.
To find the mass of the water, we can use the formula:
q = m × c × ΔT
Where:
q is the heat gained by the water (7525.4 J),
m is the mass of the water (unknown),
c is the specific heat capacity of water (4.18 J/g°C),
ΔT is the change in temperature (58°C - 24°C = 34°C).
Now we can rearrange the formula to solve for m:
m = q / (c × ΔT)
Plugging in the values, we get:
m = 7525.4 J / (4.18 J/g°C × 34°C)
m = 532.47 g
Therefore, the mass of the water in grams is approximately 532.47 g.
Since none of the options given exactly match the calculated mass, the closest option is d. 52.9.