Write the expression 3X^12+20X^6+6 in quadratic form.???
To rewrite the expression 3X^12 + 20X^6 + 6 in quadratic form, we need to make it a quadratic equation in terms of a single variable with the highest exponent of 2. However, the given expression has different exponents: 12, 6, and 0.
To convert the expression into quadratic form, we can introduce a substitution to make the highest exponent 2. Let's substitute X^6 with a new variable, let's say Y.
Let Y = X^6
Now, we can rewrite the expression using this substitution:
3Y^2 + 20Y + 6
The resulting expression, 3Y^2 + 20Y + 6, is now in quadratic form with Y as the variable.
2(x^6)^2 + 20(x^6) + 6
or let y = x^6
then
3X^12+20X^6+6
= 3y^2 + 20y + 6