Trig

A swimmer heads perpendicular to a 2-miles-per-hour current. His speed in still water is 1.8 miles per hour. Find the actual speed of the swimmer and his direction angle, 0 (the zero right here is supposed to have a line through the middle of it, I think it means cosine or something), with respect to the direction of the current.

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  1. Downstream, he is going with current, 2mph. Crosswise, he is going 1.8mph.

    Draw the diagram. I see TanTheta=1.8/2.0

    His actual speed?

    speed=sqrt(2^2+1.8^2) or
    speed=2.0/sinTheta

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    bobpursley

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