Evaluate The Exponential Equation For 3 Positive, 3 Neg. Values Of X &x=0 Y=3^-x"
Y=3^-x,x=3y=1/27,
x=-3,y=27,x=0,y=1.
is 19+20=39
y=1/3^x
x y
0 1
1 1/3
2 1/9
3 1/27
To evaluate the exponential equation y = 3^(-x) for 3 positive and 3 negative values of x, we substitute the given values of x into the equation and compute the corresponding values of y.
Let's start with positive values of x:
1. For x = 1: Substitute x = 1 into the equation y = 3^(-x)
y = 3^(-1)
y = 1/3
2. For x = 2: Substitute x = 2 into the equation y = 3^(-x)
y = 3^(-2)
y = 1/9
3. For x = 3: Substitute x = 3 into the equation y = 3^(-x)
y = 3^(-3)
y = 1/27
Now, let's move on to negative values of x:
1. For x = -1: Substitute x = -1 into the equation y = 3^(-x)
y = 3^(1)
y = 3
2. For x = -2: Substitute x = -2 into the equation y = 3^(-x)
y = 3^(2)
y = 9
3. For x = -3: Substitute x = -3 into the equation y = 3^(-x)
y = 3^(3)
y = 27
So, for the given equation y = 3^(-x), the values of y for 3 positive values of x are: y = 1/3, y = 1/9, and y = 1/27. And, the values of y for 3 negative values of x are: y = 3, y = 9, and y = 27.