gen chem

At 2273K, equilibrium constant for the reaction

2NO(g)<->N2(g)+O2(g)
Kc=2.4x10^3

What would be equilibrim concentration of N2, if initial concentration of NO was 0.1160M?

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asked by Chem
  1. Have you tried setting up an ICE chart? That's the obvious way to go.

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    posted by DrBob222
  2. yes I did, but im still not getting the right answer.

    I got .1136 which is not the correct answer.

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    posted by Chem
  3. what do you have for
    initial:


    change:

    equilibrium

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    posted by DrBob222
  4. 2NO <-> N2 O2
    initial .116 0 0
    change -x +x +x
    equil .116-x x x

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    posted by Chem
  5. Did you look at your post from last night where we arrived at K = something x 10^-192? That problem didn't ask for K, it asked for pK. I'll get back on the current problem.

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    posted by DrBob222
  6. Make it
    initial:
    NO = 0.1160
    N2 = 0
    O2 = 0

    change:
    NO = -2x
    N2 = x
    O2 = x

    equilibrium:
    NO = 0.1160 - 2x
    N2 = x
    O2 = x
    and solve for x.

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    posted by DrBob222
  7. yes, I figured that one out. Thanks so much for the help!

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    posted by Chem
  8. that works! thank you so much!!

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    posted by Chem
  9. I'm curious about the problem last night. Was the pK about 192?

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    posted by DrBob222

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