Question

Solve for x:

5^x+2=7^x-2

Answer 1

I hope you meant

5^(x+2) = 7^(x-2)
log 5^(x+2) = log 7^(x-2)
(x+2)log5 = (x-2)log7
xlog5 + 2log5 = xlog7 - 2log7
xlog5 - xlog7 = -2log7 - 2log5
x = (-2log7 - 2log5)/(log5 - log7)
x = 21.133