Please help? At least, let me know how to solve it. Please.

The Starting five (5) players of the Women’s Basketball team have agreed to make appearances for charity events tomorrow night. If you must send three of them to a Breast cancer event and the other two to a Red Cross event, how many different ways can you make the assignment?

You could name each of these players with a letter: A, B, C, D, E.

Then, group these in various ways, starting with: A B C / D E

Thanks I got it. It's 9.

its ten not nine

To solve this problem, you can use a combination formula. Since there are 5 players and you need to choose 3 for the Breast cancer event, you can think of it as selecting a group of 3 out of the 5 players.

The combination formula is given by:

C(n, r) = n! / (r! * (n - r)!)

Where n is the total number of items to choose from and r is the number of items to choose.

In this case, n = 5 (number of players) and r = 3 (number of players to select for the Breast cancer event).

Applying the formula:

C(5, 3) = 5! / (3! * (5 - 3)!)
= 5! / (3! * 2!)
= (5 * 4 * 3!) / (3! * 2!)
= (5 * 4) / 2
= 10

Therefore, there are 10 different ways to make the assignment.