How do you figure this out?
For a population that has a standard deviation of 10, what is the standard deviation of the distribution of means for samples of size 2?
A-6.33
B-7.07
C-2
D-3.03
The variance of the population is 100.
variance sample= populationvariance/n*
= 100/2=50
sample standard deviation: sqrt 50 or 7.07
This is widely used, however it is very "flaky" data. A better estimate is to put n-1 in the denominator, but anyone sampling with a sample of size two, is not anticipating very useful information anyway.
To figure out the standard deviation of the distribution of means for samples of size 2, we can use the formula:
Standard Error of the Mean (SE) = Population Standard Deviation / Square root of Sample Size
In this case, the population standard deviation is given as 10, and the sample size is 2.
Let's calculate the standard deviation using the formula:
SE = 10 / √2 ≈ 10 / 1.41 ≈ 7.07
Therefore, the standard deviation of the distribution of means for samples of size 2 is approximately 7.07.
The correct answer is B-7.07.