Chemistry

When 20.0 mL of 0.10 M NaOH are added to 20.0 mL of 0.10 M hypobromous acid, HOBr, what is the hydrogen ion concentration (H^+)? Ka for HOBr is 2 x 10^-9.

I get 5 x 10^-4. Is that right?

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asked by Mary
  1. I don't think so.
    HOBr + NaOH ==> NaOBr + H2O
    20 x 0.1 HOBr = 2 mmoles HOBr.
    20 x 0.1 NaOH = 2 mmoles NaOH

    Those two exactly neutralize each other; therefore, the pH is determined by the salt, NaOBr.
    (NaOBr) = 2 mmoles/40 mL = 0.05 M.
    It hydrolyzes as a base,
    BrO^- + HOH ==> HOBr + OH^-

    Set up ICE chart.
    Kb = (Kw/Ka) = (x)(x)/0.05
    solve for x = (OH^-) and convert to H^+.

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    posted by DrBob222

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