A 50.0G SILVER SPOON AT 20.0C IS PLACED IN A CUP OF COFFEE AT 90.0C. HOW MUCH HEAT DOES THE SPOON ABSORB FROM THE COFFEE TO REACH A TEMPERATURE OF 89.0C?
To determine the amount of heat absorbed by the silver spoon, we can use the equation:
Q = mcΔT
where:
Q = heat absorbed or released
m = mass of the object (in grams)
c = specific heat capacity of the material (in J/g°C)
ΔT = change in temperature (in °C)
First, let's calculate the change in temperature of the spoon:
ΔT = final temperature - initial temperature
ΔT = 89.0°C - 20.0°C
ΔT = 69.0°C
Next, we need to find the specific heat capacity of silver. The specific heat capacity of silver is approximately 0.235 J/g°C.
Now, let's substitute the values into the formula:
Q = mcΔT
Q = (50.0 g) * (0.235 J/g°C) * (69.0°C)
Calculating this equation gives us:
Q = 809.25 J
Therefore, the spoon absorbs approximately 809.25 Joules of heat from the coffee to reach a temperature of 89.0°C.
To calculate the amount of heat absorbed by the silver spoon, we need to use the equation:
Q = m * c * ΔT
where:
Q = heat absorbed or released (in joules)
m = mass of the object (in grams)
c = specific heat capacity of the material (in J/g°C)
ΔT = change in temperature (in °C)
Given:
Mass of the silver spoon (m) = 50.0 grams
Initial temperature of the spoon (T_initial) = 20.0°C
Final temperature of the spoon (T_final) = 89.0°C
Specific heat capacity of silver (c) = 0.235 J/g°C
Now, let's calculate the change in temperature (ΔT):
ΔT = T_final - T_initial
= 89.0°C - 20.0°C
= 69.0°C
Now, using the formula, we can calculate the amount of heat absorbed by the spoon:
Q = m * c * ΔT
= 50.0 g * 0.235 J/g°C * 69.0°C
= 810.75 J
Therefore, the silver spoon absorbs 810.75 joules of heat from the coffee in order to reach a temperature of 89.0°C.