if 160g of Al reacts with O2 to produce 260g of Al2O3.calculate the theoretical yield and the percent yield
4Al+3O2 2Al2 O3

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asked by chris
  1. 1. You have the balanced equation.
    2. Convert 160 g Al to moles. moles = grams/molar mass.
    3. Using the coefficients in the balanced equation, convert moles Al to moles Al2O3.
    4. Now convert moles Al to grams. g = moles x molar mass. This is the theoretical yield in grams.
    5. Percent yield = (actual yield/theoretical yield)*100 = ??
    The problem states that 260 g is the actual yield.

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    posted by DrBob222

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