How many moles of base are needed to neutralize 2 mol of acid for HNO3 + KOH - KNO3 + H2O?.
Can u show your work please:)
Thanks a bunch
The equation tells you that 1 mole of KOH is needed to completely react with 1 mole of HNO3; therefore, it must take 2 moles KOH to react completely with 2 moles HNO3; 3 mols KOH to react with 3 moles HNO3 or 1000 moles KOH to react completely with 1000 moles HNO3.
To determine the number of moles of base needed to neutralize the acid, we need to refer to the balanced chemical equation:
HNO3 + KOH -> KNO3 + H2O
From the balanced equation, we can see that the molar ratio between HNO3 and KOH is 1:1. This means that for every 1 mole of HNO3, we need 1 mole of KOH to neutralize it.
If we have 2 moles of HNO3, then we would also need 2 moles of KOH to completely neutralize it. This is because the molar ratio of 1:1 tells us that the number of moles required will be the same for both substances.
So, in this case, the number of moles of base needed to neutralize 2 moles of acid (HNO3) would be 2 moles of KOH.
Therefore, 2 moles of base (KOH) are needed to neutralize 2 moles of acid (HNO3).