What is the concentration (in % mass) of a solution in which you dissolve 200 mg of NaHCO3 in 1.0 L of water?
I don't know. But I can guess.
Since 200 mg is a rather small amount, it won't take up much volume, so the final volume of the solution will be VERY close to 1,000 mL and it will have a mass of VERY close to 1000 g.(actually 1000.2 g)
0.2 g/(1000.2)*100 = ??
To find the concentration in % mass, you need to know the mass of the solute (NaHCO3) and the total mass of the solution.
First, convert the mass of NaHCO3 to grams. Since 1 gram (g) is equal to 1000 milligrams (mg), the mass of NaHCO3 is 200 mg ÷ 1000 = 0.2 g.
Next, calculate the total mass of the solution. This is the sum of the mass of the solute (NaHCO3) and the mass of the solvent (water). Since you dissolve 0.2 g of NaHCO3 in 1.0 L of water, the total mass of the solution is 0.2 g + 1000 g (since 1 L of water has a mass of 1000 g) = 1000.2 g.
Now, you can calculate the concentration in % mass using the formula:
Concentration (%) = (Mass of solute / Total mass of solution) × 100
Plugging in the values, we get:
Concentration (%) = (0.2 g / 1000.2 g) × 100 = 0.01998 × 100 = 1.998%
Therefore, the concentration (in % mass) of the solution is approximately 1.998%.