# Chemistry

The S^2- ion is a relatively strong base with an equilibrium constant of 7.7x10^-1.
What is the Ka value for HS- ?

I got the equation HS^- <-> H^+ + S^-2. Am I able to find [S^-2] with the Keq?

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1. I think Ka = Kw/Kb. I'm not sure what you mean by S%2= ion has eq const of 0.77. Is that Kb?

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2. S^-2 ion has equilibrium constant of 7.7x10^-1

So it's just (1.00x10^-14)/(0.77)=1.3x10^14 = Ka HS^- ?

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3. If the equilibrium constant is the same as Kb, yes. But I'm not sure that it is. I've never seen an ION shown as an equilibrium constant.

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4. Alright, thanks! It's the correct answer on the answer key.

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