What is the molarity of H3O+ in a 4.97×10-2 M NH4Cl solution that hydrolyzes according to the equation.
NH4+(aq) + H2O(l) = H3O+(aq) + NH3(aq)
You have the equation. Set up an ICE chart and calculate H3O^+.
You will need Ka for NH4^+ and it can be calculated from Ka = Kw/Kb where Kw = 1 x 10^-14 and Kb = 1.8 x 10^-5.
To find the molarity of H3O+ in the NH4Cl solution, we need to consider the hydrolysis reaction of NH4+.
The balanced equation for the reaction is:
NH4+(aq) + H2O(l) → H3O+(aq) + NH3(aq)
Looking at the equation, we can see that 1 mole of NH4+ reacts to form 1 mole of H3O+. This means that the molar concentration of H3O+ is the same as the molar concentration of NH4+ in the solution.
Given that the molarity of NH4Cl solution is 4.97×10-2 M, we can conclude that the molarity of H3O+ in the solution is also 4.97×10-2 M.