a 14.7g ice cube is placed into 324g og water. calvulate the temperature change in the water upon complete melting of the ice. hint: determine how ,uch heat is absorbed by the melting ice and then use q=mc delta T to calculate the temperature change. use the heat of fusiion for water to calculate "q"

3.626

To calculate the temperature change in the water upon complete melting of the ice, we need to determine the amount of heat absorbed by the melting ice using the formula:

q = m × ΔHf

Where:
q = heat absorbed/released (in joules)
m = mass of the ice (in grams)
ΔHf = heat of fusion for water (in J/g)

Given:
Mass of the ice (m) = 14.7 g
Heat of fusion for water (ΔHf) = 333.5 J/g

Let's calculate the heat absorbed by the ice:

q = (14.7 g) × (333.5 J/g)
q = 4894.45 J

Now we can calculate the temperature change using the formula:

q = m × c × ΔT

Where:
q = heat absorbed/released (in joules)
m = mass of the water (in grams)
c = specific heat capacity of water (approximately 4.18 J/g°C)
ΔT = temperature change (in °C)

Given:
Mass of the water (m) = 324 g
Specific heat capacity of water (c) = 4.18 J/g°C

Substituting the values into the formula and solving for ΔT:

4894.45 J = (324 g) × (4.18 J/g°C) × ΔT

ΔT = 4894.45 J / (324 g × 4.18 J/g°C)
ΔT ≈ 3.99°C

Therefore, the temperature change in the water upon complete melting of the ice is approximately 3.99°C.

To calculate the temperature change in the water upon complete melting of the ice, we need to follow a two-step process. First, we determine the amount of heat absorbed by the melting ice, and then we use the heat absorbed to calculate the temperature change using the formula q = mcΔT.

Step 1: Calculate the heat absorbed by the melting ice.
We can calculate the heat absorbed by the ice using the formula q = m * ΔHf, where q is the heat absorbed, m is the mass of the ice, and ΔHf is the heat of fusion for water.

Given:
Mass of ice (m1) = 14.7 g
Heat of fusion for water (ΔHf) = 334 J/g

q = m1 * ΔHf
q = 14.7 g * 334 J/g

Step 2: Calculate the temperature change in the water.
Now that we have the amount of heat absorbed by the melting ice (q), we can use it to calculate the temperature change in the water using the formula q = mcΔT.

Given:
Mass of water (m2) = 324 g
Specific heat capacity of water (c) = 4.18 J/g°C (approximately)

q = mcΔT
q = m2 * c * ΔT

Rearranging the equation, we get:
ΔT = q / (m2 * c)

Substituting the values, we can now calculate the temperature change:

ΔT = (14.7 g * 334 J/g) / (324 g * 4.18 J/g°C)

Calculate this expression to find the temperature change in the water.

So what is your problem. The hint tells you exactly what I can tell you. Just do what the hint says.