How much energy is released when 2.55kg of diethyl ether freezes?

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  1. You need the latent heat of fusion. You may have been given it with the question.

    has 7.19 kJ mol-1

    so calculate the number of moles of diethyl ether relative molecular mass = 74.14

    then multiply the number of moles by the latent heat of fusion.

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  2. 533.0666 kj

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  3. How much energy is released when 1.9 kg of diethyl ether freezes? In kj

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  4. 1. Convert 2.55Kg to g
    2.55Kg x 1000g = 2550g
    2. Convert g to mol using the molar mass then multiply the heat of fusion

    2550g x 1mol x 7.27KJ = 250 KJ
    ——— ———-
    74.14g 1mol

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