A block of mass m= 100kg rests on a level ground. With what force, parallel to the ground, must you push the block so that it is just ready to start sliding? The coefficient of static between the block and ground is 0.40.
20meters
I answered this question yesterday. Just use the equation I wrote there.
http://www.jiskha.com/display.cgi?id=1272886999
To find the force required to just start sliding the block, we can use the concept of static friction.
The maximum static friction force (F_s_max) can be determined using the formula:
F_s_max = μ_s * N
Where:
μ_s is the coefficient of static friction (given as 0.40)
N is the normal force exerted on the block by the ground
In this case, the block is resting on a level ground, so the normal force (N) exerted on the block is equal to the weight of the block (mg). Therefore:
N = mg
Substituting the values:
N = (100 kg) * (9.8 m/s^2) = 980 N
Now we can find the maximum static friction force:
F_s_max = μ_s * N
= (0.40) * (980 N)
= 392 N
Hence, the force required to just start sliding the block parallel to the ground is 392 Newtons.