A rancher is putting up a rectangular electic fence to contain some horses. The rancher has 1200 feet of electric wire. The fence needs to be at least 120 feet in one direction in order to contain the barn.
Which system of linear equalities describes the conditions in this problem?
a)2w + 2l >= 1200, w >= 120
b)2w + 2l <= 1200, w <= 120
c)2w + 2l >= 1200, w <= 120
d)2w + 2l >= 1200, w >= 120
look at w, that means a or d is the answer. Then, look at perimeter, 2l+2w has to be less than 1200 ft. So, no answer is right, if you typed them correctly.
the signs are wrong the signs in the front of the equation should be equal to or less then and equal to or grater then
To determine the correct system of linear equalities, we need to consider the conditions in the problem.
First, let's define the variables:
- w: width of the fence
- l: length of the fence
The perimeter of a rectangle can be calculated using the formula: P = 2w + 2l
1. The problem states that the rancher has 1200 feet of electric wire, which means the perimeter of the fence must not exceed 1200 feet. Therefore, we can write the inequality: 2w + 2l <= 1200.
2. Additionally, the fence needs to be at least 120 feet in one direction to contain the barn. This means the width of the fence (w) must be greater than or equal to 120. Thus, we can write the inequality: w >= 120.
Combining these inequalities, the correct system of linear equalities is:
b) 2w + 2l <= 1200, w >= 120