What is the probability of a die not coming up six, six times in a row?

How do I solve that problem?

You do not need to double post.

http://www.ehow.com/how_12928_protractor.html

To solve the problem, we need to understand a few concepts. Let's break it down step by step:

1. Probability of rolling any specific number on a fair six-sided die:
Since a die has six sides, each with an equal chance of landing facing up, the probability of rolling a specific number, such as six, is 1/6.

2. Probability of not rolling a specific number on a single roll:
The probability of not rolling a specific number is the complement of rolling that number, which means it's 1 minus the probability of rolling it. In this case, the probability of not rolling a six is 1 - (1/6) = 5/6.

3. Probability of not rolling a specific number, repeatedly:
To find the probability of not rolling a specific number multiple times in a row, we multiply the probabilities of not rolling that number in each individual roll.

Now, we can calculate the probability of a die not coming up six, six times in a row:
(P(not rolling a six))^6 = (5/6)^6 ≈ 0.3349

Therefore, the probability of a die not coming up six, six times in a row is approximately 0.3349 or 33.49%.

To solve it mathematically, you raised the probability of not rolling a six (5/6) to the power of 6 because you want to calculate the probability of this outcome happening in six consecutive rolls.