what mass of so2 is produced from the reaction between 31.5g of s8 and 8.65g of o2?

I know how to find the limiting reagents and all but I need a little help knowing how to find the mass of the product.

2H20(l) = 2H2 (g) +O2 (g)

For the above, if 1.50 mg of water is decomposed, what mass of hydrogen is procduced? (1 Mg=10^6g=1 metric ton)?

What is the answer and what is the best way to solve this?

answered above

To determine the mass of SO2 produced from the reaction between S8 and O2, you need to follow these steps:

1. Write a balanced chemical equation for the reaction:

S8 + 8O2 → 8SO2

2. Calculate the molar masses of S8 and O2:

Molar mass of S8 = atomic mass of sulfur x 8 = 32.07 g/mol x 8 = 256.56 g/mol
Molar mass of O2 = atomic mass of oxygen x 2 = 16.00 g/mol x 2 = 32.00 g/mol

3. Convert the given mass of S8 and O2 to moles:

Moles of S8 = Mass of S8 / Molar mass of S8
= 31.5 g / 256.56 g/mol

Moles of O2 = Mass of O2 / Molar mass of O2
= 8.65 g / 32.00 g/mol

4. Determine the limiting reagent:

The limiting reagent is the reactant that is completely consumed and determines the amount of product formed. To find the limiting reagent, compare the moles of S8 and O2 using the stoichiometric coefficients from the balanced equation.

Since the balanced equation shows a 1:8 ratio between S8 and O2, you'll need eight times more moles of O2 than S8. Therefore, the limiting reagent is S8.

5. Calculate the moles of SO2 produced:

Since S8 is the limiting reagent, it will be fully converted to produce SO2. According to the balanced equation, one mole of S8 produces eight moles of SO2.

Moles of SO2 = Moles of S8 x (8 moles SO2 / 1 mole S8)

6. Convert moles of SO2 to grams:

Mass of SO2 = Moles of SO2 x Molar mass of SO2

To find the molar mass of SO2, add the molar masses of sulfur (32.07 g/mol) and oxygen (16.00 g/mol) together:

Molar mass of SO2 = 32.07 g/mol + 2(16.00 g/mol) = 64.07 g/mol

Mass of SO2 = Moles of SO2 x Molar mass of SO2

7. Substitute the calculated values into the equation and solve for the mass of SO2:

Mass of SO2 = (31.5 g / 256.56 g/mol) x (8 moles SO2 / 1 mole S8) x (64.07 g/mol)

Evaluate the expression to find the mass of SO2 produced.

After you know the limiting reagent, convert moles of the limiting reagent to moles of the product (using the cofficients in the balanced equation). Then moles of the product x molar mass = grams.