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Find the center, vertices, foci, and eccentricity of the ellipse. 9x^2 + 4y^2  36x + 8y + 31 = 0 I know the center is (2,1) For the vertices I had (3,1)(1,1) and the foci (3.8,1)(.20,1) and e = 1.80 but I think these are
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Find the standard form of the equation of the ellipse. (Remember center is midpoint between either foci or vertices) (1) 9x^2+4y^2+36x24y+36=0 (2) Vertices: (0,5)(0,5) Passes through the point (4,2) Centered at the origin
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let equation of an ellipse be x^2+4y^2+6x8y+9=0 a. Find the standard form of the ellipse b. Find the center c. Find the vertices d. Find the foci e. Find the eccentricity
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For the ellipse with equation 5x^2+64y^2+30x+128y211=0, find the cooridinates of the center, foci, and vertices. Then, graph the equation. my answer is: coordinates of center: (3,1) foci:(11,1) and (4.7,1) vertices: (11,1)
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