Not sure where to go next. I need to solve this quadratic equation 7x^2-5=0.
This is what I have so far, not sure where/what to do next
x=2/7
x=sqrt2/7 or x=-sqrt2/7* =+/-sqrt2/7
+/-sqrt14/7
not even sure if this is right.
7x^2 - 5 = 0
7x^2 = 5
x^2 = 5/7
x = ± √5/√7
or
x = ± √35/7
To solve the quadratic equation 7x^2 - 5 = 0, you can follow these steps:
1. Start with the equation: 7x^2 - 5 = 0.
2. Add 5 to both sides of the equation to isolate the quadratic term: 7x^2 = 5.
3. Divide both sides of the equation by 7 to make the coefficient of x^2 equal to 1: x^2 = 5/7.
4. Take the square root of both sides of the equation to solve for x: x = ±√(5/7).
So, the solutions to the quadratic equation are x = ±√(5/7).
To simplify the solution:
1. Simplify the radicals by splitting root(5/7) into √5/√7.
2. Multiply both the numerator and denominator of √5/√7 by √7 to rationalize the denominator: (√5 * √7) / (√7 * √7) = √35 / 7.
Hence, the simplified solutions to the quadratic equation 7x^2 - 5 = 0 are x = ±√35/7.