In a cyclotron, an electromagnet exerts a force of 7.50x10-13N on a beam of protons. Each proton has a mass of 1.67x10-27kg. The electromagnet causes the protons to travel in a circular path of radius 1.20m. What is the velocity of the proton beam?
I assume that your force is the force perr proton.
Mp*V^2/R is the force, 7.50x10^-13 N.
Mp is the proton mass. Solve for V
To find the velocity of the proton beam, we can use the centripetal force equation:
F = (mv^2) / r
Where:
F is the force applied by the electromagnet (7.50x10^(-13) N),
m is the mass of the proton (1.67x10^(-27) kg),
v is the velocity of the proton beam (what we want to find),
r is the radius of the circular path (1.20 m).
First, let's rearrange the equation to solve for v:
v = √(F * r / m)
Now we can substitute the given values into the equation:
v = √((7.50x10^(-13) N) * (1.20 m) / (1.67x10^(-27) kg))
Calculating this equation will give us the velocity of the proton beam.