Hi, this is a reply to the question I asked earlier. I asked about the classification and functional group of an organic compound. It has bonds between H-C-C-H.

Off of each Carbon is single bonds of Hydrogen above and below. making a total of 6 Hydrogens and two carbons. They asked the classification of the organic compound-choices are:
alkane
alkene
alkyne
none of these

I thought it would be an alkane because this is an ethane compound, I think?

Second part of same question, I rechecked the diagram, there are no OH bonds but they asked the functional group of the molecule-
choices were-
ketone
alcohol
aldehyde
carboxylic acid-

Dr. Bob, I agree it can't be any of those because it does lack OH bond-that is what is confusing me-my teacher is insisting the diagram is correct but I don't think so.

If you could just let me know if the first part that the organic molecule I described would be classified as an alkane, is that correct or not?

Thanks so much-

OK. I misunderstood about the H atoms. You have CH3CH3 which makes it an alkane, specifically, ethane.

Unless they have changed the rules about functional groups (and when I see the IUPAC rules nowdays, that may be possible), I don't see how ketones, aldehydes, carboxylic acids, or alcohols are in the picture. When you find out what is going on I would appreciate you posting it.

I'll let you know-thank you

Based on the description provided, the compound with bonds between H-C-C-H and single hydrogen bonds off each carbon is indeed an ethane molecule. Therefore, your initial intuition that it would be classified as an alkane is correct. Alkanes are hydrocarbons that only contain single bonds between carbon atoms and are therefore saturated hydrocarbons. Ethane (C2H6) is a specific example of an alkane.

Moving on to the second part of your question, you mentioned that there are no OH bonds in the molecule. This means that it does not belong to any of the functional groups listed: ketone, alcohol, aldehyde, or carboxylic acid. All of these functional groups contain an OH bond in their structure. The absence of an OH bond in the given compound suggests that none of these functional groups apply.

To summarize, the organic compound described is classified as an alkane (specifically, ethane) and does not possess any of the listed functional groups (ketone, alcohol, aldehyde, or carboxylic acid) because it lacks an OH bond.