equations trig
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find the exact solutions 2cos^2x+3sinx=0 the way it stands, that is a "nasty" question. Are you sure the second term isn't 2sin(2x) ? no, its as i wrote it. then it's got me stymied, I must be missing something rather obvious,
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how can i find all the exact solutions to the equation : 2cos^2x + 3sinx = 3 the solutions have to be between [0,2pi)
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Determine the solution of the equetion: 2cos x1=0? 2cos x=0? and 2cos x+1=0?
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1. Find y'(x) when xsecy  3y sinx = 1 a) (3ycosx  sec y) / (xsec^2y  3sinx) b) (3cosx  sec x) / (xsecytany  3sinx) c) (3ycosx  sec y) / (xsecytany  3sinx) d) (3ycosx  secytany) / xsec^2y  3sinx) This is what I did: xsecy
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