How much heat is needed to raise the temperature of 155 g of water from 25.5 Celsius to 95.0 Celsius?
q = mass x specific heat x delta T.
To calculate the amount of heat needed to raise the temperature of water, we can use the formula:
Q = m * c * ΔT
Where:
Q = heat energy (in joules)
m = mass of water (in grams)
c = specific heat capacity of water (approximately 4.18 J/g°C)
ΔT = change in temperature (in Celsius)
Given:
m = 155 g
ΔT = (95.0°C - 25.5°C) = 69.5°C
Let's substitute these values into the formula:
Q = 155 g * 4.18 J/g°C * 69.5°C
Q ≈ 45266.25 J
Therefore, approximately 45266.25 Joules of heat energy are needed to raise the temperature of 155 g of water from 25.5°C to 95.0°C.
To find out how much heat is needed to raise the temperature of water, we can use the formula:
Q = m * c * ΔT
Where:
Q is the amount of heat (in joules)
m is the mass of the water (in grams)
c is the specific heat capacity of water (which is approximately 4.186 J/g°C)
ΔT is the change in temperature (in Celsius)
Let's calculate the amount of heat required step by step:
Step 1: Convert the mass from grams to kilograms:
155 g = 0.155 kg
Step 2: Calculate the change in temperature:
ΔT = 95.0°C - 25.5°C = 69.5°C
Step 3: Plug the values into the formula:
Q = 0.155 kg * 4.186 J/g°C * 69.5°C
Q ≈ 44,968.824 Joules (or approximately 44.97 kJ)
Therefore, approximately 44.97 kilojoules of heat is needed to raise the temperature of 155 grams of water from 25.5°C to 95.0°C.